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SEC 2027 · K310 SEC 2

Sec 2 E Math
Visual Notes

Pictures first. Formulas boxed. Every exam keyword highlighted.
HOW TO STUDY WITH THIS
Read the 💡 box
the whole topic in 1 line
Study the diagram
cover it, redraw it
Learn the yellow
formulas & keywords
Redo the worked example
without looking
THE CHAPTERS
🗺️
CH 1
Proportion & Map Scales
Direct: y = kx. Inverse: y = k/x.
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CH 2
Expansion & Factorisation
3 special identities + cross method.
➗
CH 3
Algebraic Fractions & Formulae
Factorise first, then cancel.
⛰️
CH 4
Quadratic Graphs & Equations
a > 0 smile, a < 0 frown.
✖️
CH 5
Simultaneous Equations
Eliminate one letter.
↔️
CH 6
Linear Inequalities
× or ÷ by negative → flip sign.
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CH 7
Congruence & Similarity
Similar = same shape, sides in ratio.
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CH 8
Pythagoras & Trig
SOH CAH TOA.
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CH 9
Pyramids, Cones, Spheres
Pointy solids = ⅓ × base × h.
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CH 10
Statistics
Mean, median, mode + charts.
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CH 11
Probability
favourable ÷ total.
🖨 PRINTCtrl+P → Save as PDF · Scale 100% · Margins None · Background graphics ON
E Math · Sec 2 · SEC K310
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1

Proportion & Map Scales

N2 · direct & inverse proportion, scales
BIG IDEADirect: one goes up, the other goes up by the same factor → y = kx. Inverse: one up, other down → y = k/x.
xy
direct: straight line through origin
xy
inverse: curve, never touches axes
TypeEquationExample
y ∝ xy = kx5 pens cost $4 → 1 pen $0.80 → 12 pens $9.60
y ∝ x²y = kx²x doubles → y × 4
y ∝ 1/xy = k/x6 men take 10 days → 15 men take 6×10÷15 = 4 days
Write the relation with k
Substitute the given pair to find k
Write the full equation
Use it to answer

Map scales

Scale 1 : 50 000
1 cm on map = 50 000 cm = 0.5 km
length: 1 cm : 0.5 km
area: 1 cm² : 0.25 km²
Example
Lake is 6 cm² on the map → 6 × 0.25 = 1.5 km²
⚠ TRAPFor area, square the length scale — never use the length scale directly. Convert cm → km by ÷ 100 000.
E Math · Sec 2
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2

Expansion & Factorisation

N5 · identities, quadratic factorisation, grouping
BIG IDEALearn the 3 identities both ways. Factorising = expanding in reverse.
IdentityExample
(a + b)² = a² + 2ab + b²(x + 3)² = x² + 6x + 9
(a − b)² = a² − 2ab + b²(2x − 1)² = 4x² − 4x + 1
(a + b)(a − b) = a² − b²x² − 49 = (x + 7)(x − 7)

Cross method for ax² + bx + c

2x² + 7x + 3 2x+1 x+3 2x × 3 = 6xx × 1 = x sum 7x ✓
→ (2x + 1)(x + 3)
How
① split ax² into 2 factors (left)
② split c into 2 factors (right)
③ cross-multiply and add
④ must equal bx → read across the rows

Factorising checklist

Take out the common factor first
2 terms? → try a² − b²
3 terms? → identity or cross method
4 terms? → grouping
Grouping
ax + ay + bx + by
= a(x + y) + b(x + y) = (a + b)(x + y)
Common factor first
3x² − 12 = 3(x² − 4)
= 3(x + 2)(x − 2)
⚠ TRAP(a + b)² ≠ a² + b² — never forget the middle term 2ab.
E Math · Sec 2
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3

Algebraic Fractions & Formulae

N5 · simplify, ×, ÷, +, −, change the subject
BIG IDEAAlgebraic fractions work like number fractions. Factorise first, then cancel whole factors.
✂️ Simplify
(x² − 9)/(x² + 3x)
= (x + 3)(x − 3) / x(x + 3) = (x − 3)/x
✖️ Multiply / ➗ divide
÷ → flip the second fraction and ×
(2a/3b) ÷ (4a²/9b) = (2a/3b) × (9b/4a²) = 3/(2a)
➕ Add / subtract
use a common denominator
2/x + 3/(x + 1)
= [2(x + 1) + 3x] / x(x + 1) = (5x + 2)/x(x + 1)
⚠ TRAPYou can only cancel factors, never terms: (x + 3)/3 ≠ x. Put brackets round numerators when subtracting.

Changing the subject of a formula

Clear fractions (× denominator)
Expand brackets
Get all the new subject terms on one side
Factorise it out, then divide
Example 1
Make r the subject: V = πr²h
r² = V/(πh) → r = √(V/(πh))
Example 2 (subject twice)
Make x the subject: y = (x + 2)/(x − 1)
y(x − 1) = x + 2 → yx − x = y + 2
x(y − 1) = y + 2 → x = (y + 2)/(y − 1)
🧠 HOOKUndo in the reverse order of what was done to the letter: last thing done = first thing undone.
E Math · Sec 2
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4

Quadratic Graphs & Equations

N6 · N7 · parabolas, factorisation
BIG IDEAy = ax² + bx + c is a parabola: a > 0 → ∪ (minimum), a < 0 → ∩ (maximum). It is symmetric about its turning point.
xy−13min (1, −4)x = 1c = −3
y = x² − 2x − 3 = (x + 1)(x − 3)
Read the graph
roots: where it cuts the x-axis (y = 0)
y-intercept: c
line of symmetry: halfway between roots
turning point: on that line

Solve by factorisation

Make one side = 0
Factorise
Set each factor = 0
Solve both
Example
x² − 2x = 3 → x² − 2x − 3 = 0
(x + 1)(x − 3) = 0 → x = −1 or x = 3
⚠ TRAPNever divide both sides by x — you lose the root x = 0. x² = 5x → x(x − 5) = 0 → x = 0 or 5.
🧠 HOOKSketch checklist: shape (∪/∩), y-intercept, x-intercepts, line of symmetry. Label all of them.
E Math · Sec 2
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5

Simultaneous Linear Equations

N7 · elimination, substitution, graphical
BIG IDEA2 unknowns need 2 equations. Eliminate one letter, solve, then substitute back.
xy(3, 2)x + 2y = 7x − y = 1
solution = point of intersection
Elimination
x + 2y = 7 …(1)
x − y = 1 …(2)
(1) − (2): 3y = 6 → y = 2
sub into (2): x = 3
Substitution
from (2): x = y + 1
sub into (1): y + 1 + 2y = 7 → 3y = 6 → y = 2, x = 3
Which method?
one letter already alone → substitution
same coefficient → elimination (same sign subtract, different signs add)

Graphs of ax + by = c

Quick plot
put x = 0 → find y; put y = 0 → find x; join the 2 points.
2x + 3y = 12 → (0, 4) and (6, 0)
⚠ TRAPLabel equations (1) and (2) and show which you add/subtract. Check the answer in the other equation.
🧠 HOOKWord problems: let the 2 unknowns be x and y, write 2 sentences as 2 equations.
E Math · Sec 2
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6

Linear Inequalities

N7 · solving, number lines
BIG IDEASolve like an equation, but when you × or ÷ by a negative, flip the sign.
-3-2-1012345
x > 0 → open circle (not included)
-3-2-1012345
x ≤ 1 → filled circle (included)
Example
5 − 2x ≥ 11
−2x ≥ 6 → x ≤ −3 (÷ −2, flip!)
Integer answers
"largest integer x with 3x < 10" → x < 3.33 → x = 3
⚠ TRAPMultiplying/dividing by a negative reverses the inequality. Swapping sides also reverses it: 4 > x means x < 4.
🧠 HOOK< > → open circle ○ · ≤ ≥ → filled circle ●.
E Math · Sec 2
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7

Congruence & Similarity

G2 · congruent & similar figures, enlargement
BIG IDEACongruent = same shape AND size. Similar = same shape, sides in the same ratio, angles equal.
≡
congruent: equal sides & angles
48~
similar: scale factor k = 8/4 = 2

Enlargement

Scale factor k
k > 1 → enlargement
0 < k < 1 → reduction
new length = k × old length
Finding a missing side
match corresponding sides (opposite equal angles)
x / 12 = 5 / 8 → x = 7.5
⚠ TRAPMatch the sides by their equal angles, not by their position on the page. Redraw the triangles the same way round.
🧠 HOOKSec 3 adds the formal tests (SSS, SAS, ASA, RHS for congruence; AA, SSS, SAS for similarity) and area/volume ratios.
E Math · Sec 2
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8

Pythagoras & Trigonometry

G4 · right-angled triangles
BIG IDEARight-angled triangle only: a² + b² = c² (c = hypotenuse, opposite the right angle) and SOH CAH TOA.
θ hypotenuse oppadjacent
labels depend on θ
SOH CAH TOA
sin θ = opp / hyp
cos θ = adj / hyp
tan θ = opp / adj
angle → use sin⁻¹, cos⁻¹, tan⁻¹
Pythagoras example
legs 6 and 8 → c = √(36 + 64) = 10
hyp 13, leg 5 → √(169 − 25) = 12
Is it right-angled?
check if (longest)² = sum of other two²
7, 24, 25: 49 + 576 = 625 ✓
Trig example
θ = 35°, hyp = 10 → opp = 10 sin 35° = 5.74
Find an angle
opp 4, adj 7 → θ = tan⁻¹(4/7) = 29.7°
⚠ TRAPCalculator must be in DEG mode. Give angles to 1 d.p.. Label opp/adj/hyp from the angle you are using.
E Math · Sec 2
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9

Pyramids, Cones & Spheres

G5 · volume & surface area
BIG IDEAPointy solids are ⅓ of the matching prism: V = ⅓ × base area × height.
h
Pyramid
hrl
Cone
r
Sphere
SolidVolumeSurface area
Pyramid⅓ × base × hbase + all triangles
Cone⅓πr²hπrl + πr² (curved = πrl)
Sphere(4/3)πr³4πr²
Hemisphere(2/3)πr³2πr² + πr² = 3πr² (solid)
Slant height
l² = r² + h²
r = 3, h = 4 → l = 5
Example
Cone r = 3 cm, h = 4 cm
V = ⅓ × π × 9 × 4 = 37.7 cm³
Total SA = π(3)(5) + π(9) = 75.4 cm²
⚠ TRAPCurved surface of a cone uses l (slant height), volume uses h (vertical height). A solid hemisphere includes its flat circle.
🧠 HOOKCone, sphere & ½ab sin C formulas are given in the exam formula list — but you must know which to use.
E Math · Sec 2
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10

Statistics

S1 · dot diagrams, histograms, stem-and-leaf, averages
BIG IDEAMean = total ÷ count · Median = middle value (in order) · Mode = most common.
12345
Dot diagram — mode = 2
Histogram — bars touch, equal class widths
🌿 Stem-and-leaf
1 | 2 5 8
2 | 0 3 3 7
3 | 1 4
key: 1 | 2 means 12
median = 23 (5th of 9)
Which average?
mean: uses all data, affected by extreme values
median: best with outliers
mode: for categories / most popular

Mean of grouped data — use mid-values

Mass (kg)Mid xffx
40 – 50454180
50 – 605510550
60 – 70656390
Total201120
Answer
mean = Σfx ÷ Σf = 1120 ÷ 20 = 56 kg
⚠ TRAPMedian position = (n + 1) ÷ 2 after sorting. Grouped mean is an estimate because we use mid-values.
E Math · Sec 2
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11

Probability

S2 · single events
BIG IDEAP(event) = favourable outcomes ÷ total outcomes — always between 0 (impossible) and 1 (certain).
0 impossibleunlikely½ evenlikely1 certain
🎲 One die
P(even) = 3/6 = ½
P(more than 4) = 2/6 = ⅓
P(7) = 0
🃏 Bag of 3 red, 5 blue
P(red) = 3/8
P(not red) = 1 − 3/8 = 5/8
🧠 HOOKP(not A) = 1 − P(A)
⚠ TRAPAnswers as a fraction in simplest form (or decimal) — never as a ratio like 3 : 8.
✍ METHODList the outcomes (sample space) when unsure — e.g. tossing 2 coins: HH, HT, TH, TT → P(one head) = 2/4 = ½.
🧠 HOOKSec 4 adds combined events: possibility diagrams, tree diagrams, "and" (×) / "or" (+) rules.
E Math · Sec 2